## Area and Perimeter - Problem Sums

#### 1. Adriel ran 5 rounds of a square ground of side 70 m.

Find the total distance he ran.

**Step 1:**

Distance covered in 1 round of the square ground

= Perimeter of the square ground

= 70 + 70 + 70 + 70

= 280 m

**Step 2:**

Distance covered in 5 rounds of the square ground

= 5 × 280

= 1400 m

He ran a total distance of

**1400 m**.

#### 2. Mrs. Rao gives one rectangular card of sides 18 cm by 14 cm to each of her 7 pupils.

She wants her pupils to glue a ribbon around the border of their own card.

Find the length of the ribbon they will need altogether.

**Step 1:**

Perimeter of 1 card

= 18 + 14 + 18 + 14

= 64 cm

**Step 2:**

Each pupil needs 64 cm of ribbon for their card.

Hence, 7 pupils will need

= 7 × 64

= 448 cm

They will need

**448 cm**of ribbon altogether.

#### 3. Lila has 9 square stamps of side 3 cm each.

She glues them onto an envelope to form a bigger square.

What area of the envelope does the bigger square cover?

The 9 stamps can be arranged to form a square as shown below.

**Step 1:**

Side of the square formed

= 3 + 3 + 3

= 9 cm

**Step 2:**

Area of the square formed

= 9 × 9

= 81 cm

^{2}

The area of the envelope that the bigger square covers is

**81 cm**.

^{2}#### 4. Mrs. Bell cuts a 25 cm by 6 cm cloth into 5 equal pieces.

What is the area of each piece?

**Step 1:**

Area of the cloth

= 25 × 6

= 150 cm

^{2}

**Step 2:**

Area of each cloth

= 150 ÷ 5

= 30 cm

^{2}

The area of each piece is

**30 cm**.

^{2}#### 5. You have 4 squares each of side 8 cm.

Join the squares to form a bigger four-sided figure.

What is the longest possible perimeter that you can get?

Using the 4 squares we can form either a bigger square (Figure A) or a rectangle (Figure B).

**Figure A:**

Side of the big square

= Side of the small square + Side of the small square

= 8 + 8

= 16 cm

Perimeter of the big square

= 16 + 16 + 16 + 16

=

**64 cm**

**Figure B:**

Length of the rectangle

= 8 + 8 + 8 + 8

= 32 cm

Breadth of the rectangle

= 8 cm

Perimeter of the rectangle

= 32 + 8 + 32 + 8

=

**80 cm**

Hence, the longest possible perimeter that you can get is

**80 cm**.