2-Step Word Problems Involving the Four Operations
1. Mr. Baker bought a guitar and a microphone.
The guitar cost $1589 and the microphone cost $572.
If he had $3500 at first, how much money had he left after paying for the two items?
$1589 + $572 = $2161
The guitar and the microphone cost $2161 altogether.
$3500 − $2161 = $1339
He had $1339 left after paying for the two items.
The guitar and the microphone cost $2161 altogether.
$3500 − $2161 = $1339
He had $1339 left after paying for the two items.
2. 2447 children participated in a drawing competition. 1250 of them were boys. How many fewer girls than boys participated in the competition?
2447 − 1250 = 1197
There were 1197 girls.
1250 − 1197 = 53
53 fewer girls than boys participated in the competition.
There were 1197 girls.
1250 − 1197 = 53
53 fewer girls than boys participated in the competition.
3. Bakery A sold 2088 muffins.
Bakery B sold 621 more muffins than Bakery A.
What is the total number of muffins sold by the two bakeries?
2088 + 621 = 2709
Bakery B sold 2709 muffins.
2088 + 2709 = 4797
The total number of muffins sold by the two bakeries is 4797.
Bakery B sold 2709 muffins.
2088 + 2709 = 4797
The total number of muffins sold by the two bakeries is 4797.
4. Mr. Cooper made 8 boxes of cheese rolls. Each box contained 165 cheese rolls. He kept 212 for his family and sold the rest.
How many cheese rolls did he sell?
165 × 8 = 1320 (a)
He made 1320 cheese rolls.
He made 1320 cheese rolls.
1320 − 212 = 1108
He sold 1108 cheese rolls.
He sold 1108 cheese rolls.
5. Julie had some pencils and erasers. She put 3 pencils and 5 erasers into each pencil case.
She got a total of 9 pencil cases.
How many pencils and erasers were there altogether?
3 + 5 = 8 (a)
There were 8 pencils and erasers in each pencil case.
There were 8 pencils and erasers in each pencil case.
8 × 9 = 72
In 9 pencil cases, there were 72 pencils and erasers altogether.
In 9 pencil cases, there were 72 pencils and erasers altogether.
6. James, Kai and Lee liked collecting stickers. Lee had 6 times as many stickers as Kai. James had 94 more stickers than Lee. Kai had 193 stickers. How many stickers did James have?
193 × 6 = 1158
Lee had 1158 stickers.
1158 + 94 = 1252
James had 1252 stickers.
Lee had 1158 stickers.
1158 + 94 = 1252
James had 1252 stickers.
7. A bag of cake mix costs $15. Aryanna had $127 left after buying 5 bags of cake mix. Find the sum of money she had at first.
$15 × 5 = $75
The 5 bags of cake mix cost $75 altogether.
$75 + $127 = $202
She had $202 at first.
The 5 bags of cake mix cost $75 altogether.
$75 + $127 = $202
She had $202 at first.
8. Mr. Roberts had 540 bananas. He separated 76 ripe bananas. He sold the remaining bananas equally to 8 fruit stalls. How many bananas did each fruit stall get?
540 − 76 = 464
He sold 464 bananas altogether.
464 ÷ 8 = 58
Each fruit stall got 58 bananas.
He sold 464 bananas altogether.
464 ÷ 8 = 58
Each fruit stall got 58 bananas.
9. Billy bought 5 bags of balls. Each bag contained 40 balls. He packed the balls into packets of 8 balls each. How many packets did he get?
40 × 5 = 200 (a)
There were 200 balls altogether.
There were 200 balls altogether.
200 ÷ 8 = 25
He got 25 packets.
He got 25 packets.
10. A boy collects a total of 316 stamps, stickers and coins. He collects four times as many stamps as stickers. There are 46 coins. How many stickers are there?
316 − 46 = 270
There are 270 stamps and stickers.
270 ÷ 5 = 54
There are 54 stickers.
There are 270 stamps and stickers.
270 ÷ 5 = 54
There are 54 stickers.
11. There were a total of 19 chickens and goats on a farm. Adam counted 54 legs altogether. How many goats were there on the farm?
[Hint: A chicken has 2 legs. A goat has 4 legs.]
Start by counting 2 legs on each creature - chicken as well as goat - as each of them has at least 2 legs.
19 × 2 = 38
So far, we have counted 38 legs, which include both the legs on each chicken and 2 legs on each goat.
4 − 2 = 2
For each goat, we need to count 2 more legs.
54 − 38 = 16
16 legs remain to be counted.
The remaining 16 legs belong to the goats; 2 for each goat.
16 ÷ 2 = 8
There were 8 goats.
19 × 2 = 38
So far, we have counted 38 legs, which include both the legs on each chicken and 2 legs on each goat.
4 − 2 = 2
For each goat, we need to count 2 more legs.
54 − 38 = 16
16 legs remain to be counted.
The remaining 16 legs belong to the goats; 2 for each goat.
16 ÷ 2 = 8
There were 8 goats.