Evaluating Algebraic Expressions

Learn to find the value of expressions by substitution

1. What is Substitution?

The Big Idea

Substitution means replacing a letter with a number to find the value of an expression.

When we know the value of the letter, say y = 5, we can put 5 in place of y in the expression!

Example: The Magic of Substitution

If y = 5, find the value of y + 3.

Replace y with 5, then add 3

y + 3

= 5 + 3 (substitute y = 5)

= 8

2. Evaluating Addition and Subtraction

Example 1: The Stick and the Rod

A rod is y cm longer than a stick. The stick is 20 cm long.

(a) Express the length of the rod in terms of y.

Length of rod = (20 + y) cm

(b) Find the length of the rod when y = 9.

Length of rod = (20 + y) cm

= (20 + 9) cm

= 29 cm

Example 2: Hassan's Age Table

Hassan is 12 years old now. How old is he at different times?

TimeExpressionIf p = 3, q = 5, r = 5
now1212
in 3 years' time12 + 315
in p years' time12 + p12 + 3 = 15
in q years' time12 + q12 + 5 = 17
5 years ago12 - 57
r years ago12 - r12 - 5 = 7

Practice: Substitution

If n = 7, find the value of 25 - n.

ShowHide solution

25 - n

= 25 - 7 (substitute n = 7)

= 18

3. Evaluating Multiplication and Division

Remember: 4x means 4 × x. So when x = 5, we calculate 4 × 5 = 20.

Example: Cherries in Three Boxes

Box A has x cherries. Box B has 3 times as many cherries as Box A. Box C has 9 cherries.

(a) Express the total number of cherries in terms of x.

Total = x + 3x + 9

= 4x + 9

(b) Find the total number of cherries when x = 15.

Total = 4x + 9

= 4 × 15 + 9

= 60 + 9

= 69 cherries

Example: Simon and Lucas's Money

Simon has 5 times as much money as Lucas. They have a total of $q.

(a) Express the amount of money Lucas has in terms of q.

Total units = 5 + 1 = 6 units

6 units = $q

1 unit = $q ÷ 6 = $(q6)(\frac{q}{6})

(b) Find the amount of money Lucas has when q = 84.

Lucas's money = $(q6)(\frac{q}{6})

= $(84 ÷ 6)

= $14

Practice: Multiplication

If m = 8, find the value of 5m + 3.

ShowHide solution

5m + 3

= 5 × 8 + 3

= 40 + 3

= 43

4. Word Problem Evaluation

Example: Bus Rental

Mr Low rented a bus to take p students on a learning journey. He was charged $30 for rental of the bus and $6 for each student.

Bus Rental Cost
Total Cost$30$6 × p?
Bus rental ($30) + cost for p students ($6 each)

(a) Express the total amount Mr Low paid in terms of p.

Amount = $30 + $6 × p

= $30 + $6p

= $(30 + 6p)

(b) Find the total amount Mr Low paid when p = 20.

Amount = $(30 + 6p)

= $(30 + 6 × 20)

= $(30 + 120)

= $150

Practice: Word Problem

A taxi charges $3 flag-down fare plus $2 per kilometre. If the journey is k kilometres:

(a) Write the fare in terms of k.

(b) Find the fare when k = 12.

ShowHide solution

(a) Fare = $3 + $2k = $(3 + 2k)

(b) When k = 12:

Fare = $(3 + 2 × 12)

= $(3 + 24)

= $27

Practice: Division Expression

$w is shared equally among 4 friends. Each friend also receives an extra $5.

(a) Express how much each friend gets in terms of w.

(b) Find the amount each friend gets when w = 80.

ShowHide solution

(a) Each friend gets $w ÷ 4 + $5 = $(w4+5)(\frac{w}{4} + 5)

(b) When w = 80:

Each friend gets $(80 ÷ 4 + 5)

= $(20 + 5)

= $25

Steps for Evaluation

  1. Identify the expression (e.g., 4x + 9)
  2. Write down the given value (e.g., x = 15)
  3. Substitute - Replace the letter with the number
  4. Calculate - Follow order of operations (× ÷ before + -)
  5. Write the answer with units if needed

Key Takeaways

  • ✓ Substitution = replacing a letter with a number
  • ✓ When substituting, 4x means 4 × x
  • ✓ x6\frac{x}{6} means x ÷ 6
  • ✓ Multiply and divide before you add and subtract (work out anything in brackets first)
  • ✓ Check your answer makes sense in the context
  • ✓ Include units in your final answer (cm, $, etc.)

Practise this on Home Campus: Algebra Evaluate Expressions

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